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  <title>MathJax v3 with customized list of components</title>
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    <p>
    When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
    $$x = {-b \pm \sqrt{\texttip{b^2-4ac}{descriminant}} \over 2a}.$$
    </p>

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